"Thorsten Froehlich" wrote:
> You still did not understand which means I am not able
> to explain it well enough :-(

I still don't understand I'm afraid. In this one-line example:

#declare foo = function(C) {C*2}

C is not defined before the function. C *is* defined inside the function
{...} brackets. C is not defined after the function brackets. If that
doesn't mean that C is local to the function, then what does it mean?

> #declare foo = function(a,b,c)
> {
>     a +
>     #declare b = 5;
>     c + b // What is 'b' now assuming either model of operation???
> }
>
> Currently the answer is:  'b' will be substituted by '5'

That's what I want too. Only if B is declared *before* the function it
shouldn't affect the function, like here:

> #declare b = 5;
> #declare foo = function(a,b,c)
> {
>     a + c + b // What is 'b' now assuming either model of operation???
> }
> #declare q = foo(7,8,9)

In this example an error occurs, but I would like the b in the function to
be substituted with the b parameter fed to the function when it is invoked
(ie. 8), not the b variable declared before the function.

Rune
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